From the department of overthinking department, you can just use Array(1…5) and Array(“Hello”). Oh well, move on move on. 🙂 Thanks Davide De F. & Ray Fix
Trick du jour, e.g. ToArray(1…5)
From the department of overthinking department, you can just use Array(1…5) and Array(“Hello”). Oh well, move on move on. 🙂 Thanks Davide De F. & Ray Fix
Trick du jour, e.g. ToArray(1…5)
5 Comments
but you already can do Array(1 … 5)
Can you do Array(“Hello”)? Oh yes, you can! Never mind, move along, move along. 🙂
In the Swift 2.1 playground and REPL, Array(“Hello”) results in “error: missing argument label ‘arrayLiteral:’ in call” but Array(“Hello”.characters) works.
I was playing with a minimal way to generate an array of ascending objects:
given a class decl such as:
class mc {
let k : Int
init(inK:Int) { k = inK }
}
let objArray = (1…3).map{ x in mc(inK:x) }
Updated a bit for Swift 3 and as an extension:
extension Sequence {
func toArray() -> [Iterator.Element] {
return Array(self)
}
}